5/x 1-2/y-1=1/2 10/x 1 2/y-1=5/2 by cross multiplication 138978

Steps for Solving Linear Equation y=2x1 y = 2 x − 1 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 2x1=y 2 x − 1 = y Add 1 to both sides Add 1 to both sidesAlgebra Graph y= (x1)^25 y = (x − 1)2 − 5 y = ( x 1) 2 5 Find the properties of the given parabola Tap for more steps Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k k a = 1 a = 1 h = 1 h = 1 k = − 5 k = 5 5/x12/y1=1/2 10/x12/y1=5/2 by cross multiplication Maths Simultaneous Linear Equations

3 X Y 2 X Y 2 9 X Y 4 X Y 1

5/x 1-2/y-1=1/2 10/x 1 2/y-1=5/2 by cross multiplication

5/x 1-2/y-1=1/2 10/x 1 2/y-1=5/2 by cross multiplication- 1/x=1/5 therefore x=5 substituting x=5 in 5/x12/y1=1/2 5/52y=1/2 12y=1/2 taking LCM y2/y=1/2 cross multiplying 2y2=y10/ (x1) 2 (y1) =5/2 where x ≠ 1 and y ≠ 1 Sarthaks eConnect Largest Online Education Community

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 Solve the following simultaneous equations 2/x 3/y = 15; Answer Let 1/x be u and 1/y be v therefore, 5u2v=1/2eqn (i) 10u2v=5/2eqn (ii) on solving (i) and (ii) 2v and 2v gets canceled hence, 15u=38/x 5/y = 77 asked in Linear Equations by RakshitKumar ( 356k points) linear equations in two variables

Simple and best practice solution for Y1=5(x2) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve itGraph y5=1/2*(x2) Move all terms not containing to the right side of the equation Tap for more steps Add to both sides of the equation Add and Rewrite in slopeintercept form Tap for more steps The slopeintercept form is , where is the slope and is the yintercept Reorder termsSteps for Solving Linear Equation y= \frac { 1 } { 2 } x5 y = 2 1 x − 5 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side \frac {1} {2}x5=y 2 1 x − 5 = y Add 5 to both sides Add 5 to both sides

 Transcript Example 18 Solve the following pair of equations by reducing them to a pair of linear equations 5/(𝑥 −1) 1/(𝑦 −2) = 2 6/(𝑥 −1) – 3/(𝑦 −2) = 1 5/(𝑥 − 1) 1/(𝑦 − 2) = 2 6/(𝑥 − 1) – 3/(𝑦 − 2) = 1 So, our equations become 5u v = 2 6u – 3v = 1 Thus, our equations are 5u v = 2 (3) 6u – 3v = 1 (4) From (3) 5u v = 2 v = 2 Solve the following systems of equations 5/ (x1) 2/ (y1) = 1/2 ;

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